The angles of a triangle are in the ratio 2: | vedclass

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Given: Ratio of angles is $2: 3: 4$.To find: Angles of the triangle.Let the angles of the triangle be $\angle A, \angle B,$ and $\angle C$.Therefore,$

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Given: Ratio of angles is $2: 3: 4$.To find: Angles of the triangle.Let the angles of the triangle be $\angle A, \angle B,$ and $\angle C$.Therefore,$\angle A = 2x$,$\angle B = 3x$,and $\angle C = 4x$.In $	riangle ABC$,the sum of angles is $\angle A + \angle B + \angle C = 180^{\circ}$ (Angle Sum Property of a triangle).Substituting the values: $2x + 3x + 4x = 180^{\circ}$.$9x = 180^{\circ} \Rightarrow x = 180^{\circ} / 9 = 20^{\circ}$.Therefore,$\angle A = 2 	imes 20^{\circ} = 40^{\circ}$,$\angle B = 3 	imes 20^{\circ} = 60^{\circ}$,and $\angle C = 4 	imes 20^{\circ} = 80^{\circ}$.Hence,the angles of the triangle are $40^{\circ}, 60^{\circ},$ and $80^{\circ}$.

The angles of a triangle are in the ratio $2: 3: 4$. Find the angles of the triangle.

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