The acceleration of a body is to be doubled f | vedclass

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(B) According to Newton's second law of motion,the force $F$ acting on a body is given by the product of its mass $m$ and acceleration $a$,expressed a

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two

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(B) According to Newton's second law of motion,the force $F$ acting on a body is given by the product of its mass $m$ and acceleration $a$,expressed as $F = m 	imes a$.If the mass $m$ of the body remains constant,the force $F$ is directly proportional to the acceleration $a$ $(F \propto a)$.If the acceleration is doubled $(a' = 2a)$,then the new force $F'$ will be $F' = m 	imes (2a) = 2 	imes (m 	imes a) = 2F$.Therefore,the acting force must be increased by a factor of $2$.

Body	Mass $(kg)$	Speed $(m s^{-1})$
$A$	$1$	$10$
$B$	$2$	$9$

The acceleration of a body is to be doubled from its initial value. By what factor is the acting force to be increased?

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