The area of the region bounded by the curve y | vedclass

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Question

(A) The area $A$ of the region bounded by the curve $y = f(x)$,the $x$-axis,and the lines $x = a$ and $x = b$ is given by the formula $A = \int_{a}^{b

Vedclass · Accepted Answer

$\frac{4}{3}$

Vedclass · Answer

(A) The area $A$ of the region bounded by the curve $y = f(x)$,the $x$-axis,and the lines $x = a$ and $x = b$ is given by the formula $A = \int_{a}^{b} |f(x)| \, dx$. Given the curve $y = -2\sqrt{x}$,the lines $x = 0$ and $x = 1$,and the $x$-axis $(y = 0)$,the area is: $A = \int_{0}^{1} |-2\sqrt{x}| \, dx$ $A = \int_{0}^{1} 2\sqrt{x} \, dx$ $A = 2 \int_{0}^{1} x^{1/2} \, dx$ $A = 2 \left[ \frac{x^{3/2}}{3/2} ight]_{0}^{1}$ $A = 2 	imes \frac{2}{3} [x^{3/2}]_{0}^{1}$ $A = \frac{4}{3} (1^{3/2} - 0^{3/2})$ $A = \frac{4}{3}$ sq. units. Thus,the correct option is $A$.

The area of the region bounded by the curve $y = -2\sqrt{x}$ and the lines $x = 0$,$x = 1$,and $y = 0$ is . . . . . . sq. units.

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