The average age of 11 players of a cricket te | vedclass

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(C) Let the sum of the ages of the original $11$ players be $S$.The average age of the original team is $S/11$.When two players aged $18$ and $20$ are

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$19\, 	ext{years } 11\, 	ext{months}$

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(C) Let the sum of the ages of the original $11$ players be $S$.The average age of the original team is $S/11$.When two players aged $18$ and $20$ are replaced by two new players with ages $x$ and $y$,the new sum of ages becomes $S - 18 - 20 + x + y = S + (x + y - 38)$.The new average age is $(S + x + y - 38) / 11$.According to the problem,the average age increases by $2$ months ($1/6$ of a year):$(S + x + y - 38) / 11 = S/11 + 2/12$Multiplying by $11$:$S + x + y - 38 = S + 22/12$$x + y - 38 = 22 	ext{ months}$$x + y = 38 	ext{ years } 22 	ext{ months}$.The average age of the two new players is $(x + y) / 2 = (38 	ext{ years } 22 	ext{ months}) / 2 = 19 	ext{ years } 11 	ext{ months}$.

The average age of $11$ players of a cricket team is increased by $2$ $months$ when two of them aged $18\, years$ and $20\, years$ are replaced by two new players. The average age of the new players is:

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