The average of $n$ numbers $x_{1}, x_{2}, \ldots, x_{n}$ is $\bar{x}$. Then,the value of $\sum_{i=1}^{n}(x_{i}-\bar{x})$ is equal to

  • A
    $n$
  • B
    $0$
  • C
    $n\bar{x}$
  • D
    $\bar{x}$

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