(D) The capacitance of a parallel plate capacitor with air is given by $C_{0} = 6\, \mu F$.When a dielectric medium is introduced,the new capacitance

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(D) The capacitance of a parallel plate capacitor with air is given by $C_{0} = 6\, \mu F$.When a dielectric medium is introduced,the new capacitance is $C_{m} = 30\, \mu F$.The dielectric constant $\epsilon_{r}$ is defined as the ratio of the capacitance with the medium to the capacitance with air:$\epsilon_{r} = \frac{C_{m}}{C_{0}} = \frac{30}{6} = 5$.The permittivity of the medium $\epsilon$ is given by $\epsilon = \epsilon_{0} \cdot \epsilon_{r}$.Substituting the given values:$\epsilon = 8.85 \times 10^{-12} \times 5 = 44.25 \times 10^{-12} = 0.4425 \times 10^{-10} \approx 0.44 \times 10^{-10} C^{2} N^{-1} m^{-2}$.

Class 12 Physics Electrostatic Potential and Capacitance Effect of Dielectric Inside Capacitor

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The capacitance of a parallel plate capacitor with air as medium is $6\, \mu F$. With the introduction of a dielectric medium,the capacitance becomes $30\, \mu F$. The permittivity of the medium is..........$C^{2} N^{-1} m^{-2}$.
$(\varepsilon_{0} = 8.85 \times 10^{-12} C^{2} N^{-1} m^{-2})$

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A
$5.00$
B
$0.44 \times 10^{-13}$
C
$1.77 \times 10^{-12}$
D
$0.44 \times 10^{-10}$

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Effect of Dielectric Inside Capacitor

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The capacitance of a parallel plate capacitor with air as medium is $6\, \mu F$. With the introduction of a dielectric medium,the capacitance becomes $30\, \mu F$. The permittivity of the medium is..........$C^{2} N^{-1} m^{-2}$.$(\varepsilon_{0} = 8.85 \times 10^{-12} C^{2} N^{-1} m^{-2})$

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Two identical parallel plate air capacitors are connected in series to a battery of emf $V$. If one of the capacitors is inserted in a liquid of dielectric constant $K$,then the potential difference across the other capacitor will become:

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The capacitance of a parallel plate capacitor with air as medium is $6\, \mu F$. With the introduction of a dielectric medium,the capacitance becomes $30\, \mu F$. The permittivity of the medium is..........$C^{2} N^{-1} m^{-2}$.
$(\varepsilon_{0} = 8.85 \times 10^{-12} C^{2} N^{-1} m^{-2})$