The capacitive reactance of a capacitor $C$ is $X \ \Omega$. Both the frequency of the $A.C.$ supply and the capacitance of the capacitor are doubled. The new capacitive reactance will be:
- A$\frac{X}{4} \ \Omega$
- B$\frac{X}{2} \ \Omega$
- C$2 X \ \Omega$
- D$4 X \ \Omega$
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