The chord $PQ$ of the parabola $y^2 = x$,where one end $P$ of the chord is at point $(4, -2)$,is perpendicular to the axis of the parabola. Then the slope of the normal at $Q$ is

  • A
    $-4$
  • B
    $-\frac{1}{4}$
  • C
    $4$
  • D
    $\frac{1}{4}$

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