The circumference of 2 circles is 88 , m and | vedclass

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(D) For the smaller circle,the circumference is $C_1 = 2 \pi r_1 = 88 \, m$.$r_1 = \frac{88 	imes 7}{2 	imes 22} = 14 \, m$.Area $A_1 = \pi r_1^2 =

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(D) For the smaller circle,the circumference is $C_1 = 2 \pi r_1 = 88 \, m$.$r_1 = \frac{88 	imes 7}{2 	imes 22} = 14 \, m$.Area $A_1 = \pi r_1^2 = \frac{22}{7} 	imes 14 	imes 14 = 616 \, m^2$.For the larger circle,the circumference is $C_2 = 2 \pi r_2 = 220 \, m$.$r_2 = \frac{220 	imes 7}{2 	imes 22} = 35 \, m$.Area $A_2 = \pi r_2^2 = \frac{22}{7} 	imes 35 	imes 35 = 3850 \, m^2$.The difference between the areas is $A_2 - A_1 = 3850 - 616 = 3234 \, m^2$.

The circumference of $2$ circles is $88 \, m$ and $220 \, m$ respectively. What is the difference between the area of the larger circle and the smaller circle? (in $m^2$)

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