The circumference of the base of a cylindrica | vedclass

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Question

(C) Let the base radius of the cylindrical vessel be $r \,cm$.The circumference of the base is given by $2 \pi r$.$2 \pi r = 132$$2 	imes \frac{22}{7

Vedclass · Accepted Answer

$34.65$

Vedclass · Answer

(C) Let the base radius of the cylindrical vessel be $r \,cm$.The circumference of the base is given by $2 \pi r$.$2 \pi r = 132$$2 	imes \frac{22}{7} 	imes r = 132$$r = \frac{132 	imes 7}{2 	imes 22} = 21 \,cm$.The height of the vessel is $h = 25 \,cm$.The volume of a cylinder is given by $V = \pi r^2 h$.$V = \frac{22}{7} 	imes (21)^2 	imes 25$$V = \frac{22}{7} 	imes 21 	imes 21 	imes 25 = 22 	imes 3 	imes 21 	imes 25 = 34650 \,cm^3$.Since $1000 \,cm^3 = 1 \,l$,the capacity in litres is $\frac{34650}{1000} = 34.65 \,l$.Thus,the vessel can hold $34.65 \,l$ of water.

The circumference of the base of a cylindrical vessel is $132 \,cm$ and its height is $25 \,cm$. How many litres of water can it hold (in $,l$)? $(1000 \,cm^3 = 1 \,l)$ Assume $\pi = \frac{22}{7}$.

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