The coordinates of a point on the parabola y^ | vedclass

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(A) The equation of the parabola is $y^2 = 8x$. Comparing this with $y^2 = 4ax$,we get $4a = 8$,so $a = 2$. The focal distance of a point $(x, y)$ on

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$(2, \pm 4)$

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(A) The equation of the parabola is $y^2 = 8x$. Comparing this with $y^2 = 4ax$,we get $4a = 8$,so $a = 2$. The focal distance of a point $(x, y)$ on the parabola $y^2 = 4ax$ is given by $x + a$. Given that the focal distance is $4$,we have $x + 2 = 4$,which implies $x = 2$. Substituting $x = 2$ into the parabola equation $y^2 = 8(2)$,we get $y^2 = 16$,so $y = \pm 4$. Thus,the coordinates of the point are $(2, \pm 4)$.

The coordinates of a point on the parabola $y^2 = 8x$ whose focal distance is $4$ are

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