The coagulation of 200 mL of a positive coll | vedclass

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(D) The flocculation value is defined as the minimum concentration of an electrolyte in $mmol \ L^{-1}$ required to cause the coagulation of a colloid

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(D) The flocculation value is defined as the minimum concentration of an electrolyte in $mmol \ L^{-1}$ required to cause the coagulation of a colloid.Given: Volume of colloid $= 200 \ mL$, Mass of $HCl = 0.73 \ g$.Molar mass of $HCl = 36.5 \ g \ mol^{-1}$.Number of moles of $HCl = \frac{0.73 \ g}{36.5 \ g \ mol^{-1}} = 0.02 \ mol = 20 \ mmol$.Since $200 \ mL$ of the colloid requires $20 \ mmol$ of $HCl$ for coagulation, we calculate the amount required for $1000 \ mL$ (or $1 \ L$):Flocculation value $= \frac{20 \ mmol}{200 \ mL} 	imes 1000 \ mL = 100 \ mmol \ L^{-1}$.Thus, the flocculation value is $100$.

List-$I$	List-$II$
$A$. Dialysis	$IV$. Purification of colloidal mixture
$B$. Peptization	$I$. Precipitate converts to colloidal mixture
$C$. Flocculation	$II$. Precipitation of colloidal mixture
$D$. Gold number	$III$. Protective power

The coagulation of $200 \ mL$ of a positive colloid took place when $0.73 \ g$ of $HCl$ was added to it without changing the volume much. The flocculation value of $HCl$ for the colloid is

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