The coefficient of apparent expansion of a li | vedclass

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(D) The real coefficient of expansion of a liquid is constant and is given by the relation: $\gamma_{	ext{real}} = \gamma_{	ext{apparent}} + \gamma_

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$\frac{\gamma_1 - \gamma_2}{3} + \alpha$

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(D) The real coefficient of expansion of a liquid is constant and is given by the relation: $\gamma_{	ext{real}} = \gamma_{	ext{apparent}} + \gamma_{	ext{vessel}}$.For vessel $A$,the coefficient of volume expansion is $\gamma_{v,A} = 3\alpha$. Thus,$\gamma_{	ext{real}} = \gamma_1 + 3\alpha$.For vessel $B$,let the coefficient of linear expansion be $\alpha_B$. Then the coefficient of volume expansion is $\gamma_{v,B} = 3\alpha_B$. Thus,$\gamma_{	ext{real}} = \gamma_2 + 3\alpha_B$.Since $\gamma_{	ext{real}}$ is the same for the liquid in both cases,we equate the two expressions:$\gamma_1 + 3\alpha = \gamma_2 + 3\alpha_B$.Rearranging for $\alpha_B$:$3\alpha_B = \gamma_1 - \gamma_2 + 3\alpha$.$\alpha_B = \frac{\gamma_1 - \gamma_2}{3} + \alpha$.

The coefficient of apparent expansion of a liquid,when determined using two different vessels $A$ and $B$,are $\gamma_1$ and $\gamma_2$ respectively. If the coefficient of linear expansion of vessel $A$ is $\alpha$,then the coefficient of linear expansion of vessel $B$ is:

Similar Questions

Give the value of the coefficient of volume expansion at room temperature for an ideal gas.

The relation between the coefficient of real expansion $(\gamma_r)$ and coefficient of apparent expansion $(\gamma_a)$ of a liquid and the coefficient of linear expansion $(\alpha_g)$ of the material of the container is:

The coefficient of apparent expansion of a liquid when determined using two different vessels $A$ and $B$ are ${\gamma _1}$ and ${\gamma _2}$ respectively. If the coefficient of linear expansion of vessel $A$ is $\alpha $,the coefficient of linear expansion of vessel $B$ is

Which of the following curves represent the variation of coefficient of volume expansion of an ideal gas at constant pressure?

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