The combination of the gates shown will produ | vedclass

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(D) Let the inputs be $A$ and $B$. The circuit consists of two $NOT$ gates, two $AND$ gates, and one $OR$ gate.$1$. The upper $AND$ gate receives inpu

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$XOR$ gate

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(D) Let the inputs be $A$ and $B$. The circuit consists of two $NOT$ gates, two $AND$ gates, and one $OR$ gate.$1$. The upper $AND$ gate receives inputs $A'$ (from $NOT$ gate) and $B$. Its output is $A' \cdot B = \bar{A}B$.$2$. The lower $AND$ gate receives inputs $A$ and $B'$ (from $NOT$ gate). Its output is $A \cdot B' = A\bar{B}$.$3$. The final $OR$ gate combines these outputs: $Y = \bar{A}B + A\bar{B}$.$4$. The Boolean expression $Y = \bar{A}B + A\bar{B}$ is the standard definition of an $XOR$ gate (Exclusive $OR$ gate).Therefore, the combination produces an $XOR$ gate.

The combination of the gates shown will produce:

Similar Questions

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