The compound X (C_{7}H_{9}N) reacts with benz | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Benzene sulphonyl chloride,also known as Hinsberg's reagent,reacts with $1^{\circ}$ and $2^{\circ}$ amines to form sulphonamides.The sulphonamide

Vedclass · Accepted Answer

Vedclass · Answer

(A) Benzene sulphonyl chloride,also known as Hinsberg's reagent,reacts with $1^{\circ}$ and $2^{\circ}$ amines to form sulphonamides.The sulphonamide formed from a $1^{\circ}$ amine contains an acidic hydrogen atom attached to the nitrogen,making it soluble in alkali.The sulphonamide formed from a $2^{\circ}$ amine does not contain any acidic hydrogen atom attached to the nitrogen,making it insoluble in alkali.Given that compound $X (C_{7}H_{9}N)$ reacts with benzene sulphonyl chloride to form a product $Y$ that is insoluble in alkali,$X$ must be a $2^{\circ}$ amine.Among the given options,$N$-methylaniline $(C_{6}H_{5}NHCH_{3})$ is a $2^{\circ}$ amine,which satisfies the given conditions.

The compound $X (C_{7}H_{9}N)$ reacts with benzene sulphonyl chloride to give $Y (C_{13}H_{13}NO_{2}S)$ which is insoluble in alkali. The compound $X$ is

Similar Questions

Identify the major product of the following sequence of reactions:

The reaction given below is known as:
$ArN_2^+ X^- + Cu_2Cl_2 + HCl \to ArCl + N_2 + Cu_2Cl_2$

What is the major product formed when $C_6H_5NH_2$ reacts with $CHCl_3$ and $KOH$?

In which of the following reactions is a primary amine not obtained as a product?

The strongest conjugate acid will result from:

Vedclass Test Series

Exam Paper Generator

Online Exam Module