The compound formed by passing ethylene gas into a cold alkaline solution of $KMnO_4$ is:

  • A
    Ethyl alcohol
  • B
    Acetaldehyde
  • C
    Acetic acid
  • D
    Ethylene glycol

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$2.$ $CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$

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