What will be the major product of each of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In reaction $1$,the quaternary ammonium hydroxide undergoes Hofmann elimination. Due to the steric bulk of the leaving group $-N^{+}(CH_3)_3$,the

Vedclass · Accepted Answer

$1-Y, 2-X$

Vedclass · Answer

(B) In reaction $1$,the quaternary ammonium hydroxide undergoes Hofmann elimination. Due to the steric bulk of the leaving group $-N^{+}(CH_3)_3$,the less substituted alkene,$1$-butene $(Y)$,is the major product. In reaction $2$,the alkyl halide undergoes dehydrohalogenation following Zaitsev's rule,where the more substituted alkene,$2$-butene $(X)$,is the major product. Therefore,the correct answer is $1-Y, 2-X$.

What will be the major product of each of the two reactions shown below?
$1.$ $CH_3-CH_2-CH(N^{+}(CH_3)_3)OH^{-} \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$
$2.$ $CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$

Similar Questions

The reaction $CH_2 = CH - CH_3 + HBr \rightarrow CH_3CHBr - CH_3$ is

Which process converts $1$-butene into butane?

Addition of $Br_2$ to $trans-2-butene$ would give a product which is

In organic reactions, sodium in liquid ammonia is used as:

The ozonolysis products of an olefin are $CHO-CHO$ and $CHO-CH_2-CH_2-CHO$. The olefin is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What will be the major product of each of the two reactions shown below? $1.$ $CH_3-CH_2-CH(N^{+}(CH_3)_3)OH^{-} \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$ $2.$ $CH_3-CH_2-CH(Br)-CH_3 \xrightarrow{\text{heat}} CH_3-CH=CH-CH_3 (X) + CH_3-CH_2-CH=CH_2 (Y)$