The compound from which formic acid cannot be | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Formic acid $(HCOOH)$ cannot be prepared from methyl magnesium bromide $(CH_{3}MgBr)$ because Grignard reagents react with $CO_{2}$ to form carbox

Vedclass · Accepted Answer

methyl magnesium bromide

Vedclass · Answer

(D) Formic acid $(HCOOH)$ cannot be prepared from methyl magnesium bromide $(CH_{3}MgBr)$ because Grignard reagents react with $CO_{2}$ to form carboxylic acids with at least two carbon atoms (e.g.,acetic acid). Formic acid can be prepared from the other reagents as follows: $(a)$ $CH_{3}OH$ $\xrightarrow{[O]} HCHO$ $\xrightarrow{[O]} HCOOH$ $(b)$ $CO + NaOH$ $\longrightarrow HCOONa$ $\xrightarrow{H_{2}SO_{4}} HCOOH + NaHSO_{4}$ $(c)$ Glycerol + Oxalic acid $\xrightarrow{383 \ K} HCOOH + 	ext{glycerol}$

The compound from which formic acid cannot be prepared is

Similar Questions

Pyruvic acid is obtained by

In the reaction $CH_3CN \xrightarrow{H_3O^+, \text{heat}} CH_3COOH$,what is the change in the hybridization state of the functional carbon atom?

$CO_2$ on reaction with ethyl magnesium bromide gives

In the reaction,$x$,$y$ and $z$ are

$A \xrightarrow[\begin{smallmatrix} (ii) CN^{-} \\ (iii) H_{2}O/H^{+} \end{smallmatrix}]{(1) Cl_{2}, \Delta }$ $4-$Bromophenyl acetic acid.
In the above reaction '$A$' is ....

Vedclass Test Series

Exam Paper Generator

Online Exam Module