The compounds A and B are respectively | vedclass

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(D) $1$. Reaction of benzaldehyde with methanol in the presence of dry $HCl$ gas leads to the formation of an acetal, $A$, which is benzaldehyde dimet

Vedclass · Accepted Answer

$Ph-CH(OMe)_2$ and $Ph-CH=CH-CO_2H$

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(D) $1$. Reaction of benzaldehyde with methanol in the presence of dry $HCl$ gas leads to the formation of an acetal, $A$, which is benzaldehyde dimethyl acetal, $Ph-CH(OMe)_2$.$2$. Treatment of the acetal $A$ with dilute $HCl$ results in its hydrolysis back to benzaldehyde $(Ph-CHO)$ and methanol.$3$. The subsequent reaction of benzaldehyde with acetic anhydride $((CH_3CO)_2O)$ in the presence of sodium acetate $(CH_3COONa)$ is the Perkin condensation reaction, which yields cinnamic acid $(Ph-CH=CH-COOH)$ as the final product $B$.

The compounds $A$ and $B$ are respectively

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