The compounds X and Y are respectively: | vedclass

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(D) $1$. Formation of $X$: The reaction of $p$-bromotoluene with $Mg$ in ether forms a Grignard reagent, $p-CH_3-C_6H_4-MgBr$. This reacts with acetal

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$p$-toluic acid and $p$-toluidine

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(D) $1$. Formation of $X$: The reaction of $p$-bromotoluene with $Mg$ in ether forms a Grignard reagent, $p-CH_3-C_6H_4-MgBr$. This reacts with acetaldehyde $(CH_3CHO)$ followed by hydrolysis to give $1-(p-tolyl)ethanol$. The haloform reaction $(Br_2/NaOH)$ on this secondary alcohol oxidizes it to $p$-methylacetophenone, which then undergoes haloform reaction again to produce $p$-toluic acid $(X)$.$2$. Formation of $Y$: $p$-toluic acid $(X)$ reacts with $SOCl_2$ to form $p$-toluoyl chloride, which on reaction with $NH_3$ gives $p$-toluamide. Finally, the Hoffman bromamide reaction $(Br_2/NaOH)$ converts the amide into $p$-toluidine $(Y)$.

List-$I$	List-$II$
$I.$ Benzenesulphonyl Chloride	$A.$ Zwitterion
$II.$ Sulphanilic acid	$B.$ Hinsberg reagent
$III.$ Alkyl Diazonium salts	$C.$ Dyes
$IV.$ Aryl Diazonium salts	$D.$ Conversion to alcohols

The compounds $X$ and $Y$ are respectively:

Similar Questions

The correct option$(s)$ for the following sequence of reactions is(are):
$(A)$ $Q = KNO_2, W = LiAlH_4$
$(B)$ $R =$ benzenamine,$V = KCN$
$(C)$ $Q = AgNO_2, R =$ phenylmethanamine
$(D)$ $W = LiAlH_4, V = AgCN$

In the given reaction,identify the final product.

$E \xleftarrow{KOH/Br_2} D \xleftarrow{H_2O_2/OH^{-} \atop (Partial \ Hydrolysis)} C \xleftarrow{NaCN} C_2H_5-Cl$ $\xrightarrow{AgCN} A$ $\xrightarrow{LiAlH_4} B$
What is the relationship between $B$ and $E$?

Match the compounds given in List-$I$ with the items given in List-$II$.

List-$I$ List-$II$

$I.$ Benzenesulphonyl Chloride $A.$ Zwitterion

$II.$ Sulphanilic acid $B.$ Hinsberg reagent

$III.$ Alkyl Diazonium salts $C.$ Dyes

$IV.$ Aryl Diazonium salts $D.$ Conversion to alcohols

Which of the following reactions does $NOT$ yield an amine?

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