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Question

(B) The van der Waals equation for a real gas is $(P + \frac{a}{V^2})(V - b) = RT$. At high pressure,the term $\frac{a}{V^2}$ is negligible compared t

Vedclass · Accepted Answer

$1 + \frac{Pb}{RT}$

Vedclass · Answer

(B) The van der Waals equation for a real gas is $(P + \frac{a}{V^2})(V - b) = RT$. At high pressure,the term $\frac{a}{V^2}$ is negligible compared to $P$. Thus,the equation simplifies to $P(V - b) = RT$. Expanding this,we get $PV - Pb = RT$. Dividing both sides by $RT$,we get $\frac{PV}{RT} - \frac{Pb}{RT} = 1$. Since the compressibility factor $Z = \frac{PV}{RT}$,we have $Z - \frac{Pb}{RT} = 1$. Therefore,$Z = 1 + \frac{Pb}{RT}$. Hence,the correct option is $B$.

The compressibility factor for a real gas at high pressure is

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