The coordinates of A and B are (3, -6) and (- | vedclass

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(D) Let the required point be $P(x, y)$ and the ratio be $m:n = 3:2$.Given $A(x_1, y_1) = (3, -6)$ and $B(x_2, y_2) = (-2, -1)$.Using the section form

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$(0, -3)$

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(D) Let the required point be $P(x, y)$ and the ratio be $m:n = 3:2$.Given $A(x_1, y_1) = (3, -6)$ and $B(x_2, y_2) = (-2, -1)$.Using the section formula,the coordinates of $P$ are given by:$x = \frac{mx_2 + nx_1}{m+n} = \frac{3(-2) + 2(3)}{3+2} = \frac{-6 + 6}{5} = \frac{0}{5} = 0$$y = \frac{my_2 + ny_1}{m+n} = \frac{3(-1) + 2(-6)}{3+2} = \frac{-3 - 12}{5} = \frac{-15}{5} = -3$Therefore,the coordinates of $P$ are $(0, -3)$.

The coordinates of $A$ and $B$ are $(3, -6)$ and $(-2, -1)$. The coordinates of $P$ dividing $\overline{AB}$ from $A$ in ratio $3:2$ are $\ldots \ldots \ldots \ldots$

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