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(A) The coordinates of $D$ which divides $AB$ in the ratio $l : k$ are given by the section formula:$D = \left( \frac{l x_2 + k x_1}{l + k}, \frac{l y

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$\left( \frac{k x_1 + l x_2 + m x_3}{k + l + m}, \frac{k y_1 + l y_2 + m y_3}{k + l + m} \right)$

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(A) The coordinates of $D$ which divides $AB$ in the ratio $l : k$ are given by the section formula:$D = \left( \frac{l x_2 + k x_1}{l + k}, \frac{l y_2 + k y_1}{l + k} \right)$Now,$P$ divides the line segment $DC$ in the ratio $m : (k + l)$.Using the section formula for $P$ with $D = (x_D, y_D)$ and $C = (x_3, y_3)$:$P = \left( \frac{m x_3 + (k + l) x_D}{m + k + l}, \frac{m y_3 + (k + l) y_D}{m + k + l} \right)$Substituting the coordinates of $D$:$x_P = \frac{m x_3 + (k + l) \left( \frac{l x_2 + k x_1}{l + k} \right)}{k + l + m} = \frac{m x_3 + l x_2 + k x_1}{k + l + m}$Similarly,$y_P = \frac{m y_3 + l y_2 + k y_1}{k + l + m}$Thus,the coordinates of $P$ are $\left( \frac{k x_1 + l x_2 + m x_3}{k + l + m}, \frac{k y_1 + l y_2 + m y_3}{k + l + m} \right)$.

The coordinates of the points $A, B, C$ are $(x_1, y_1)$,$(x_2, y_2)$,$(x_3, y_3)$ and $D$ divides the line $AB$ in the ratio $l : k$. If $P$ divides the line $DC$ in the ratio $m : k + l$,then the coordinates of $P$ are

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