The correct electron affinity order is (EA = | vedclass

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Question

(B) Electron affinity is the energy released when an electron is added to a gaseous species. It is directly related to the stability of the species fo

Vedclass · Accepted Answer

$O^{+} > N^{+} > NO^{+}$

Vedclass · Answer

(B) Electron affinity is the energy released when an electron is added to a gaseous species. It is directly related to the stability of the species formed after electron gain.$N^{+} (1s^{2} 2s^{2} 2p^{2})$: Adding an electron gives $N$ $(1s^{2} 2s^{2} 2p^{3})$,which has a stable half-filled $p$-orbital configuration.$O^{+} (1s^{2} 2s^{2} 2p^{3})$: Adding an electron gives $O$ $(1s^{2} 2s^{2} 2p^{4})$,which is less stable than the half-filled state.$NO^{+}$: This is an isoelectronic species with $N_{2}$ ($14$ electrons). Adding an electron to $NO^{+}$ leads to $NO$ ($15$ electrons),where the electron enters the antibonding $\pi^{*}$ orbital,which is less favorable.Comparing the effective nuclear charge $(Z_{eff})$,$O^{+}$ has a higher $Z_{eff}$ than $N^{+}$,but the stability of the resulting neutral atom is the dominant factor here. The correct order of electron affinity is $O^{+} > N^{+} > NO^{+}$.

The correct electron affinity order is $(EA = -\Delta H_{EG})$

Similar Questions

The electron affinity values are negative for:
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$C$. $O^{-} \rightarrow O^{2-}$
$D$. $Na \rightarrow Na^{-}$
$E$. $Al \rightarrow Al^{-}$
Choose the most appropriate answer from the options given below:

In comparison with alkali metals,the electron affinity of halogens is

Which one of the elements has the maximum electron affinity?

In which of the following cases will the maximum energy be released?

In which of the following pairs,electron gain enthalpies of constituent elements are nearly the same or identical?
$A$. $Rb$ and $Cs$
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