The correct order for the rate of decarboxyla | vedclass

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(A) The rate of decarboxylation is directly proportional to the stability of the carbanion intermediate formed after the loss of $CO_2$.The $-NO_2$ gr

Vedclass · Accepted Answer

$IV > I > III > II$

Vedclass · Answer

(A) The rate of decarboxylation is directly proportional to the stability of the carbanion intermediate formed after the loss of $CO_2$.The $-NO_2$ group is a strong electron-withdrawing group ($-I$ and $-M$ effect),which stabilizes the carbanion.In compound $(IV)$,there are two $-NO_2$ groups (at ortho and para positions),providing maximum stabilization.In compound $(I)$,the $-NO_2$ group is at the ortho position,which provides strong stabilization due to the $-I$ effect.In compound $(III)$,the $-NO_2$ group is at the para position,providing stabilization via $-I$ and $-M$ effects,but it is further from the carbanion center compared to the ortho position.In compound $(II)$,the $-NO_2$ group is at the meta position,providing stabilization only via the $-I$ effect.Thus,the stability order of the carbanions is $(IV) > (I) > (III) > (II)$.Therefore,the correct order for the rate of decarboxylation is $IV > I > III > II$.

The correct order for the rate of decarboxylation of the following compounds with sodalime will be:

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