The correct order of atomic radii of C,Al,and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The atomic radius decreases across a period from left to right due to an increase in effective nuclear charge,and it increases down a group due to

Vedclass · Accepted Answer

$C < S < Al$

Vedclass · Answer

(D) The atomic radius decreases across a period from left to right due to an increase in effective nuclear charge,and it increases down a group due to the addition of new shells.$C$ (Carbon) is in period $2$,group $14$.$S$ (Sulfur) is in period $3$,group $16$.$Al$ (Aluminum) is in period $3$,group $13$.Comparing $C$ and $S$: $C$ is in period $2$ and $S$ is in period $3$,so $C Comparing $S$ and $Al$: Both are in period $3$. $Al$ is in group $13$ and $S$ is in group $16$. Since atomic radius decreases across a period,$S  S$.Thus,the order is $C < S < Al$.

The correct order of atomic radii of $C$,$Al$,and $S$ is

Similar Questions

Identify the correct order in which the covalent radius of the following elements increases: $(I) \ Ti, (II) \ Ca, (III) \ Sc$.

In $K^{+} F^{-}$ ionic,the ionic radius of $F^{-}$ is more,while the atomic radius of $K^{+}$ is:

If the ionic radii of $K^{+}$ and $F^{-}$ are nearly the same (i.e.,$1.34 \ \mathring{A}$),then the atomic radii of $K$ and $F$ respectively are

For $Na^{+}$,$Mg^{2+}$,$F^{-}$,and $O^{2-}$; the correct order of increasing ionic radii is

What is the method to estimate the volume of an individual atom?

Vedclass Test Series

Exam Paper Generator

Online Exam Module