In K^{+} F^{-} ionic,the ionic radius of F^{- | vedclass

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(B) The correct option is $B$. $K^{+}$ and $F^{-}$ are isoelectronic species,both having $18$ electrons $(1s^2 2s^2 2p^6 3s^2 3p^6)$. However,$K^{+}$

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More than $F^{-}$

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(B) The correct option is $B$. $K^{+}$ and $F^{-}$ are isoelectronic species,both having $18$ electrons $(1s^2 2s^2 2p^6 3s^2 3p^6)$. However,$K^{+}$ has $Z = 19$ (protons) and $F^{-}$ has $Z = 9$ (protons). Since $K^{+}$ has a higher nuclear charge,its ionic radius is smaller than $F^{-}$. However,the question asks for the atomic radius of $K$ (which is $K$ atom) compared to the ionic radius of $F^{-}$. The atomic radius of $K$ ($19$ electrons,$4$ shells) is significantly larger than the ionic radius of $F^{-}$ ($10$ electrons,$2$ shells).

In $K^{+} F^{-}$ ionic,the ionic radius of $F^{-}$ is more,while the atomic radius of $K^{+}$ is:

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