The correct order of basic strength of the fo | vedclass

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(A) $I$. Piperidine is the most basic. The $N$ lone pair is in an $sp^3$ hybrid orbital,there is no resonance,and due to the $+I$ effect of the alkyl

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$I > III > II > IV$

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(A) $I$. Piperidine is the most basic. The $N$ lone pair is in an $sp^3$ hybrid orbital,there is no resonance,and due to the $+I$ effect of the alkyl group attached,it becomes more basic than $sp^3$ hybridized ammonia.$II$. In pyridine,the lone pair is in an $sp^2$ hybridized orbital. The $sp^2$ hybrid is smaller than $sp^3$,so there is a stronger attraction to the nucleus,making it less basic.$III$. $NH_3$ is more basic than aniline because in ammonia,the lone pair is localized and easily available for donation.$IV$. The basicity of aniline is lower than that of ammonia because in aniline,the lone pair of electrons on $N$ is involved in resonance with the benzene ring.Therefore,the correct order of basic strength is $I > III > II > IV$.

The correct order of basic strength of the following amines is

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