The correct order of decreasing basic strengt | vedclass

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(B) The basic strength of aromatic amines depends on the availability of the lone pair of electrons on the nitrogen atom.Electron-donating groups $(ED

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$II > I > IV > III$

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(B) The basic strength of aromatic amines depends on the availability of the lone pair of electrons on the nitrogen atom.Electron-donating groups $(EDG)$ increase basicity by increasing electron density on the nitrogen atom,while electron-withdrawing groups $(EWG)$ decrease basicity.$(II)$ $p$-Methoxyaniline has a $-OCH_3$ group,which is a strong electron-donating group ($+M$ effect),making it the most basic.$(I)$ Aniline has no substituent.$(IV)$ $m$-Nitroaniline has a $-NO_2$ group at the meta position,which exerts only an electron-withdrawing inductive effect ($-I$ effect).$(III)$ $p$-Nitroaniline has a $-NO_2$ group at the para position,which exerts a strong electron-withdrawing effect through both resonance $(-M)$ and induction $(-I)$,making it the least basic.Therefore,the order of decreasing basic strength is: $II > I > IV > III$.

The correct order of decreasing basic strength of the following compounds is:
$(I)$ Aniline
$(II)$ $p$-Methoxyaniline
$(III)$ $p$-Nitroaniline
$(IV)$ $m$-Nitroaniline

Similar Questions

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The correct order of decreasing basic strength of the following compounds is:$(I)$ Aniline$(II)$ $p$-Methoxyaniline$(III)$ $p$-Nitroaniline$(IV)$ $m$-Nitroaniline