The correct order of decreasing basic strengt | vedclass

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(A) The basic strength of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$1$. In $x$ (piperidine),the nitrogen

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$x > z > y$

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(A) The basic strength of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$1$. In $x$ (piperidine),the nitrogen is $sp^3$-hybridized,and its lone pair is localized,making it the most basic.$2$. In $z$ ($3$,$4$,$5$,$6$-tetrahydropyridine),the nitrogen is $sp^2$-hybridized. Due to higher $s$-character,the lone pair is held more tightly by the nucleus,making it less basic than $x$.$3$. In $y$ (the amide derivative),the lone pair on nitrogen is delocalized through resonance with the adjacent carbonyl group $(C=O)$,making it the least basic.Therefore,the decreasing order of basic strength is $x > z > y$.

The correct order of decreasing basic strengths of $x$ (piperidine),$y$ (caprolactam derivative),and $z$ ($3$,$4$,$5$,$6$-tetrahydropyridine) is:

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