The correct order of decreasing field strength of the below given ligands is
$I$. $NCS^{-}$ $II$. $S^{2-}$ $III$. $en$ $IV$. $SCN^{-}$
| $I$. $NCS^{-}$ | $II$. $S^{2-}$ |
| $III$. $en$ | $IV$. $SCN^{-}$ |
- A$I > II > IV > III$
- B$III > II > IV > I$
- C$III > I > IV > II$
- D$III > IV > I > II$
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Similar Questions
Complete removal of both the axial ligands (along the $z-$ axis) from an octahedral complex leads to which of the following splitting patterns? (relative orbital energies not on scale)
DifficultJEE MAIN 2019
View SolutionMatch the electronic configurations in List-$I$ with appropriate metal complex ions in List-$II$ and choose the correct option.
[Atomic Number: $Fe=26, Mn=25, Co=27$]
List-$I$ List-$II$ $P$. $t_{2g}^6 e_g^0$ $1$. $[Fe(H_2O)_6]^{2+}$ $Q$. $t_{2g}^3 e_g^2$ $2$. $[Mn(H_2O)_6]^{2+}$ $R$. $e^2 t_2^3$ $3$. $[Co(NH_3)_6]^{3+}$ $S$. $t_{2g}^4 e_g^2$ $4$. $[FeCl_4]^{-}$ $5$. $[CoCl_4]^{2-}$
[Atomic Number: $Fe=26, Mn=25, Co=27$]
| List-$I$ | List-$II$ |
| $P$. $t_{2g}^6 e_g^0$ | $1$. $[Fe(H_2O)_6]^{2+}$ |
| $Q$. $t_{2g}^3 e_g^2$ | $2$. $[Mn(H_2O)_6]^{2+}$ |
| $R$. $e^2 t_2^3$ | $3$. $[Co(NH_3)_6]^{3+}$ |
| $S$. $t_{2g}^4 e_g^2$ | $4$. $[FeCl_4]^{-}$ |
| $5$. $[CoCl_4]^{2-}$ |
MediumIIT 2023
View SolutionWhy are low spin tetrahedral complexes not formed?
Crystal field splitting energy $(CFSE)$ for $[CoCl_6]^{4-}$ is $18000 \ cm^{-1}$. The crystal field splitting energy $(CFSE)$ for $[CoCl_4]^{2-}$ will be (in $cm^{-1}$)
MediumKCET 2022
View SolutionWhich of the following ligands will cause the smallest crystal field splitting?
Medium
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