The correct order of second I.E. of C,N,O,and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The electronic configurations of the neutral atoms are:${}_{6}C: 1s^2 2s^2 2p^2$${}_{7}N: 1s^2 2s^2 2p^3$${}_{8}O: 1s^2 2s^2 2p^4$${}_{9}F: 1s^2 2

Vedclass · Accepted Answer

$O > F > N > C$

Vedclass · Answer

(D) The electronic configurations of the neutral atoms are:${}_{6}C: 1s^2 2s^2 2p^2$${}_{7}N: 1s^2 2s^2 2p^3$${}_{8}O: 1s^2 2s^2 2p^4$${}_{9}F: 1s^2 2s^2 2p^5$To find the second ionization energy $(IE_2)$,we look at the configurations of the unipositive ions $(M^+)$:$C^+: 1s^2 2s^2 2p^1$$N^+: 1s^2 2s^2 2p^2$$O^+: 1s^2 2s^2 2p^3$$F^+: 1s^2 2s^2 2p^4$$O^+$ has a half-filled $2p$ subshell $(2p^3)$,which provides extra stability,making its $IE_2$ the highest.Comparing the remaining ions,$F^+$ has a higher effective nuclear charge than $N^+$,and $N^+$ has a higher effective nuclear charge than $C^+$.Therefore,the correct order of second ionization enthalpy is $O > F > N > C$.

The correct order of second $I.E.$ of $C$,$N$,$O$,and $F$ is:

Similar Questions

$A$ neutral atom will have the lowest ionization potential when its electronic configuration is

The correct order of second ionization potential of carbon,nitrogen,oxygen and fluorine is

In which of the following electronic configurations of an element is there a very large difference between the second and third ionization energy?

The correct order in which the first ionisation potential increases is

The first ionization enthalpies of $Na, Mg$ and $Si$ are respectively $496, 737$ and $786 \ kJ \ mol^{-1}$. What would be the first ionization enthalpy of $Al$ in $kJ \ mol^{-1}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module