The correct order of spin-only magnetic momen | vedclass

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Question

(D) The complex having a higher number of unpaired electrons will have a higher value of spin-only magnetic moment.In all these complexes,the central

Vedclass · Accepted Answer

$[MnCl_4]^{2-} > [CoCl_4]^{2-} > [NiCl_4]^{2-} > [ZnCl_4]^{2-}$

Vedclass · Answer

(D) The complex having a higher number of unpaired electrons will have a higher value of spin-only magnetic moment.In all these complexes,the central metal ion is in the $+2$ oxidation state.$Zn^{2+}$ $(3d^{10})$ has $0$ unpaired electrons.$Ni^{2+}$ $(3d^8)$ has $2$ unpaired electrons.$Co^{2+}$ $(3d^7)$ has $3$ unpaired electrons.$Mn^{2+}$ $(3d^5)$ has $5$ unpaired electrons.Since the magnetic moment $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons,the order of magnetic moments is determined by the number of unpaired electrons.Therefore,the correct order is $[MnCl_4]^{2-} > [CoCl_4]^{2-} > [NiCl_4]^{2-} > [ZnCl_4]^{2-}$.

The correct order of spin-only magnetic moments among the following is: (Atomic number: $Mn = 25, Co = 27, Ni = 28, Zn = 30$)

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