The correct order of the ionic radii of O^{2- | vedclass

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(C) All the given ions $(N^{3-}, O^{2-}, F^{-}, Na^{+}, Mg^{2+}, Al^{3+})$ are isoelectronic,meaning they all have $10$ electrons.For isoelectronic sp

Vedclass · Accepted Answer

$Al^{3+} < Mg^{2+} < Na^{+} < F^{-} < O^{2-} < N^{3-}$

Vedclass · Answer

(C) All the given ions $(N^{3-}, O^{2-}, F^{-}, Na^{+}, Mg^{2+}, Al^{3+})$ are isoelectronic,meaning they all have $10$ electrons.For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.The atomic numbers are: $N (7), O (8), F (9), Na (11), Mg (12), Al (13)$.Therefore,the order of increasing ionic radius is: $Al^{3+} < Mg^{2+} < Na^{+} < F^{-} < O^{2-} < N^{3-}$.

The correct order of the ionic radii of $O^{2-}, N^{3-}, F^{-}, Mg^{2+}, Na^{+}$ and $Al^{3+}$ is

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