The correct set of four quantum numbers for t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of rubidium atom $(Z = 37)$ is $[Kr] 5s^1$.The valence electron is in the $5s$ orbital.For the $5s$ orbital,the princ

Vedclass · Accepted Answer

$5, 0, 0, +1/2$

Vedclass · Answer

(C) The electronic configuration of rubidium atom $(Z = 37)$ is $[Kr] 5s^1$.The valence electron is in the $5s$ orbital.For the $5s$ orbital,the principal quantum number $(n)$ is $5$.For an $s$-orbital,the azimuthal quantum number $(l)$ is $0$.Since $l = 0$,the magnetic quantum number $(m_l)$ is $0$.The spin quantum number $(m_s)$ can be either $+1/2$ or $-1/2$.Thus,the set of quantum numbers is $(n = 5, l = 0, m_l = 0, m_s = +1/2)$.Therefore,the correct option is $C$.

The correct set of four quantum numbers for the valence electron of rubidium atom $(Z = 37)$ is

Similar Questions

The angular wave function $A(\theta, \phi)$ for a given atomic orbital is $\frac{1}{2}\sqrt{\frac{3}{\pi}}\cos \theta$ in the polar coordinate system. Identify the orbital.

Write about $p$-orbitals.

The correct set of four quantum numbers for the valence electron of rubidium atom $(Z=37)$ is:

The electronic configuration of the element with atomic number $27$ is:

The orientation of an atomic orbital is given by ........ .

Vedclass Test Series

Exam Paper Generator

Online Exam Module