The correct set of four quantum numbers for t | vedclass

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Question

(A) The electronic configuration of Rubidium $(Z=37)$ is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1$.The valence electron is present in the $5s$

Vedclass · Accepted Answer

$n=5, l=0, m=0, s=+1/2$

Vedclass · Answer

(A) The electronic configuration of Rubidium $(Z=37)$ is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1$.The valence electron is present in the $5s$ orbital.For the $5s$ orbital,the principal quantum number $n=5$.Since it is an $s$-orbital,the azimuthal quantum number $l=0$.For $l=0$,the magnetic quantum number $m=0$.The spin quantum number $s$ can be $+1/2$ or $-1/2$. Thus,the set is $(5, 0, 0, +1/2)$.

The correct set of four quantum numbers for the valence electron of rubidium atom $(Z=37)$ is:

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