The correct stability order of carbocations is
- A$(CH_3)_3C^{+} > CH_3-CH_2^+ > (CH_3)_2CH^{+} > CH_3^+$
- B$CH_3^+ > (CH_3)_2CH^{+} > CH_3-CH_2^+ > (CH_3)_3C^+$
- C$(CH_3)_3C^{+} > (CH_3)_2CH^{+} > CH_3-CH_2^+ > CH_3^+$
- D$CH_3^+ > CH_3-CH_2^+ > (CH_3)_2CH^{+} > (CH_3)_3C^+$
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Similar Questions
The stability of the following carbocations follows the order:
$I. (CH_3)_3C^{\oplus}$
$II. (CH_3)_2C^{\oplus}(OCH_3)$
$III. CH_3CH_2CH_2CH_2^{\oplus}$
$IV. CH_3CH^{\oplus}CH_2CH_3$
$I. (CH_3)_3C^{\oplus}$
$II. (CH_3)_2C^{\oplus}(OCH_3)$
$III. CH_3CH_2CH_2CH_2^{\oplus}$
$IV. CH_3CH^{\oplus}CH_2CH_3$
DifficultKVPY 2017
View SolutionArrange the $(C-H)$ bonds $x, y$ and $z$ in decreasing order of their bond dissociation energies in homolysis.
Medium
View SolutionChlorine $\left(Cl^{17}\right)$ free radical contains how many electrons around the nucleus?
Which free radical is most stable among the following?
The increasing order of stability of the following free radicals is:
DifficultAIEEE 2006
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