The critical temperatures of gases A, B, C, a | vedclass

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(D) The extent of physical adsorption of a gas on a solid surface is directly proportional to its ease of liquefaction.Easier liquefaction is indicate

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$A$

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(D) The extent of physical adsorption of a gas on a solid surface is directly proportional to its ease of liquefaction.Easier liquefaction is indicated by a higher critical temperature $(T_c)$.Therefore,gases with higher critical temperatures are adsorbed to a greater extent.The critical temperatures are: $B (630 \ K) > D (400 \ K) > C (261 \ K) > A (190 \ K)$.Thus,the order of adsorption is $B > D > C > A$.The gas with the lowest critical temperature will have the least amount adsorbed.Hence,gas $A$ has the least quantity adsorbed.

The critical temperatures of gases $A, B, C,$ and $D$ are $190 \ K, 630 \ K, 261 \ K,$ and $400 \ K$ respectively. The quantity of gas adsorbed per gram of charcoal at the same pressure is least for the gas:

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