The cumulative distribution function $F(x)$ of a discrete random variable $X$ is given by the following table:
$X = x$$-1$$0$$1$$2$
$F(X = x)$$0.3$$0.7$$0.8$$1$

Then $E(X^2) = $

  • A
    $0.2$
  • B
    $1.2$
  • C
    $0.8$
  • D
    $2.5$

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In a game,a man wins $₹ 40$ if he gets $5$ or $6$ on a throw of a fair die and loses $₹ 20$ for getting any other number on the die. If he decides to throw the die either until he gets a $5$ or $6$ or to a maximum of $3$ throws,then his expected gain/loss (in rupees) is:

$A$ random variable $X$ has the following probability distribution:
$X$$0$$1$$2$
$P(X)$$\frac{25}{36}$$k$$\frac{1}{36}$

If the mean of the random variable $X$ is $\frac{1}{3}$,then the variance is:

$A$ $1$-rupee coin,a $2$-rupee coin,a $5$-rupee coin,and a $10$-rupee coin are tossed simultaneously. The expected value of the sum of the values of the coins that show heads up is:

The probability distribution of a random variable $X$ is given by the following table:
$X = x_i$$3$$5$$7$$9$
$P(X = x_i)$$k$$2k$$3k$$4k$

Then the standard deviation of $X$ is

Which of the following can not be a valid assignment of probabilities for outcomes of sample space $S = \{\omega_{1}, \omega_{2}, \omega_{3}, \omega_{4}, \omega_{5}, \omega_{6}, \omega_{7}\}$?
OutcomeProbability
$\omega_{1}$$0.1$
$\omega_{2}$$0.01$
$\omega_{3}$$0.05$
$\omega_{4}$$0.03$
$\omega_{5}$$0.01$
$\omega_{6}$$0.2$
$\omega_{7}$$0.6$

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