The current amplification factor of a transistor in common emitter configuration is $80$. If the emitter current is $2.43 \text{ mA}$, then the base current is (in $\mu \text{A}$)

According to a graph drawn between the input and output voltages of a transistor connected in common emitter configuration, the region in which the transistor acts as a switch is

In the following common emitter configuration, an $NPN$ transistor with current gain $\beta = 100$ is used. The output voltage of the amplifier will be

If the value of $R_e$ is zero then voltage gain is $200$. Find the voltage gain when $R_e$ is $2 \, k\Omega$.

$A$ transistor is used in common-emitter mode in an amplifier circuit. When a signal of $10 \, mV$ is added to the base-emitter voltage, the base current changes by $10 \, \mu A$ and the collector current changes by $1.5 \, mA$. The load resistance is $5 \, k\Omega$. The voltage gain of the transistor will be

If the base current is $100 \mu A$ and the collector current is $3 \ mA$,then the values of $\beta$,$\alpha$,and $I_e$ are respectively: