The de-Broglie wavelength of a particle of mass $6.63 \ g$ moving with a velocity of $100 \ ms^{-1}$ is

  • A
    $10^{-33} \ m$
  • B
    $10^{-35} \ m$
  • C
    $10^{-31} \ m$
  • D
    $10^{-25} \ m$

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For which of the following does the mathematical expression $\lambda = \frac{h}{p}$ stand?

The de Broglie wavelength of an electron in the $4^{th}$ Bohr orbit is (in $\pi a_{0}$)

Observe the following graph for the de-Broglie wavelength of a hypothetical charged particle $(q = 1.6 \times 10^{-19} \ C)$. Find the mass of the particle $(h = 6.0 \times 10^{-34} \ J \cdot s)$.

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The wavelength of an electron and a neutron will become equal when the velocity of the electron is $x$ times the velocity of the neutron. The value of $x$ is (Nearest Integer). (Mass of electron is $9.1 \times 10^{-31} \ kg$ and mass of neutron is $1.6 \times 10^{-27} \ kg$)

The velocity $v$ of a de Broglie wave is given by
$\left[ \begin{array}{c} u = \text{Frequency} \\ m = \text{mass} \\ C = \text{Velocity of light} \end{array} \right]$

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