The de Broglie wavelength of a proton is twic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The de-Broglie wavelength $\lambda$ of a particle is given by $\lambda = \frac{h}{\sqrt{2mK}}$,where $h$ is Planck's constant,$m$ is the mass,and

Vedclass · Accepted Answer

$1: 1$

Vedclass · Answer

(A) The de-Broglie wavelength $\lambda$ of a particle is given by $\lambda = \frac{h}{\sqrt{2mK}}$,where $h$ is Planck's constant,$m$ is the mass,and $K$ is the kinetic energy.From this,we have $\lambda \propto \frac{1}{\sqrt{mK}}$,which implies $K \propto \frac{1}{m\lambda^2}$.Given that $\lambda_p = 2\lambda_\alpha$ and knowing the mass of an alpha particle $m_\alpha \approx 4m_p$:$\frac{K_p}{K_\alpha} = \frac{m_\alpha}{m_p} 	imes \left( \frac{\lambda_\alpha}{\lambda_p} ight)^2$Substituting the values:$\frac{K_p}{K_\alpha} = \left( \frac{4m_p}{m_p} ight) 	imes \left( \frac{\lambda_\alpha}{2\lambda_\alpha} ight)^2$$\frac{K_p}{K_\alpha} = 4 	imes \frac{1}{4} = 1$Therefore,the ratio of the kinetic energies is $1: 1$.

The de Broglie wavelength of a proton is twice the de Broglie wavelength of an alpha particle. The ratio of the kinetic energies of the proton and the alpha particle is

Similar Questions

Which of the following has the largest de Broglie wavelength?

If the kinetic energy of a particle in motion is decreased by $36 \%$,the increase in de Broglie wavelength of the particle is (in $\%$)

An electron microscope works on the principle of......

If $\lambda_0$ is the de-Broglie wavelength for a proton accelerated through a potential difference of $100 \ V$,the de-Broglie wavelength for an $\alpha$-particle accelerated through the same potential difference is

$A$ long pipe is filled with small granules of nickel. The interatomic spacing for nickel is $d$. $A$ beam of electrons having different energies is incident on the left flat face of the pipe. Mass of electron is $m$. The beam of electrons coming out of the right flat face has energy:

Vedclass Test Series

Exam Paper Generator

Online Exam Module