The diamagnetic species is

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(A) To determine the magnetic property,we look at the electronic configuration of the central metal ion and the nature of the ligand:$1$. In $[Ni(CN)_

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$[Ni(CN)_4]^{2-}$

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(A) To determine the magnetic property,we look at the electronic configuration of the central metal ion and the nature of the ligand:$1$. In $[Ni(CN)_4]^{2-}$,$Ni$ is in the $+2$ oxidation state $(3d^8)$. $CN^-$ is a strong field ligand,causing pairing of electrons in the $3d$ orbitals,resulting in no unpaired electrons. Thus,it is diamagnetic.$2$. In $[NiCl_4]^{2-}$,$Ni^{2+}$ $(3d^8)$ is bonded to $Cl^-$ (a weak field ligand),which does not cause pairing,resulting in two unpaired electrons. Thus,it is paramagnetic.$3$. In $[CoCl_4]^{2-}$,$Co^{2+}$ $(3d^7)$ is bonded to $Cl^-$ (a weak field ligand),resulting in three unpaired electrons. Thus,it is paramagnetic.$4$. In $[CoF_6]^{2-}$,$Co^{4+}$ $(3d^5)$ is bonded to $F^-$ (a weak field ligand),resulting in five unpaired electrons. Thus,it is paramagnetic.Therefore,the correct option is $A$.

List-$I$	List-$II$
$a. [Fe(CN)_{6}]^{3-}$	$i. 5.92 \ BM$
$b. [Fe(H_{2}O)_{6}]^{3+}$	$ii. 0 \ BM$
$c. [Fe(CN)_{6}]^{4-}$	$iii. 4.90 \ BM$
$d. [Fe(H_{2}O)_{6}]^{2+}$	$iv. 1.73 \ BM$

Similar Questions

Which of the following inner orbital complexes exhibits both geometrical and optical isomerism?

Which of the following planar complex is diamagnetic and shows stereo isomerism?

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$a. [Fe(CN)_{6}]^{3-}$ $i. 5.92 \ BM$

$b. [Fe(H_{2}O)_{6}]^{3+}$ $ii. 0 \ BM$

$c. [Fe(CN)_{6}]^{4-}$ $iii. 4.90 \ BM$

$d. [Fe(H_{2}O)_{6}]^{2+}$ $iv. 1.73 \ BM$

Choose the correct answer from the options given below.

$[Ti(H_2O)_6]^{3+}$ is paramagnetic in nature due to

Select the paramagnetic molecule$(s)$ from the following:

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