(C) Radius of the garden $r_2 = \frac{\text{diameter}}{2} = \frac{210}{2} = 105 \,m$.Radius of the garden excluding the path $r_1 = 105 - 7 = 98 \,m$.

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(C) Radius of the garden $r_2 = \frac{\text{diameter}}{2} = \frac{210}{2} = 105 \,m$.Radius of the garden excluding the path $r_1 = 105 - 7 = 98 \,m$.Area of the path in the form of a circular ring is given by the difference between the area of the outer circle and the inner circle.Area of the path $= \pi r_2^2 - \pi r_1^2$$= \pi(r_2^2 - r_1^2)$$= \pi(r_2 + r_1)(r_2 - r_1)$$= \frac{22}{7} \times (105 + 98) \times (105 - 98)$$= \frac{22}{7} \times 203 \times 7$$= 22 \times 203$$= 4466 \,m^2$.

Class 10 Mathematics Areas Related to Circles Areas of Sector and Segment of a Circle

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The diameter of a circular garden is $210 \,m$. Inside it,all along the boundary,there is a path of uniform width $7 \,m$. Then,the area of the path is $\ldots \ldots \ldots \ldots \,m^2$.

A
$2310$
B
$735$
C
$4466$
D
$4455$

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Areas Related to Circles

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Areas of Sector and Segment of a Circle

In a circle with radius $14 \, cm$,$\overline{OA}$ and $\overline{OB}$ are radii perpendicular to each other. Then,the area of the minor sector corresponding to $\angle AOB$ is $\ldots \ldots \ldots \, cm^2$.

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$\overline{ OA }$ and $\overline{ OB }$ are radii of a circle perpendicular to each other. If $OA = 5.6 \, cm$,then the area of the minor sector formed by those radii is .......... $cm^2$.

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If $\theta$ is the angle (in degrees) of a sector of a circle of radius $r$,then the area of the sector is:

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Area of a sector of a circle of radius $36 \, cm$ is $54 \pi \, cm^{2}$. Find the length of the corresponding arc of the sector (in $cm$). (in $\pi$)

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As shown in the diagram,$\overline{OA}$ and $\overline{OB}$ are two radii of $\odot(O, 35 \text{ cm})$ perpendicular to each other. If $OD = 12 \text{ cm}$,find the area of the shaded region. (in $\text{cm}^2$)

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The diameter of a circular garden is $210 \,m$. Inside it,all along the boundary,there is a path of uniform width $7 \,m$. Then,the area of the path is $\ldots \ldots \ldots \ldots \,m^2$.

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In a circle with radius $14 \, cm$,$\overline{OA}$ and $\overline{OB}$ are radii perpendicular to each other. Then,the area of the minor sector corresponding to $\angle AOB$ is $\ldots \ldots \ldots \, cm^2$.

$\overline{ OA }$ and $\overline{ OB }$ are radii of a circle perpendicular to each other. If $OA = 5.6 \, cm$,then the area of the minor sector formed by those radii is .......... $cm^2$.

If $\theta$ is the angle (in degrees) of a sector of a circle of radius $r$,then the area of the sector is:

Area of a sector of a circle of radius $36 \, cm$ is $54 \pi \, cm^{2}$. Find the length of the corresponding arc of the sector (in $cm$). (in $\pi$)

As shown in the diagram,$\overline{OA}$ and $\overline{OB}$ are two radii of $\odot(O, 35 \text{ cm})$ perpendicular to each other. If $OD = 12 \text{ cm}$,find the area of the shaded region. (in $\text{cm}^2$)

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