The difference between the squares of two con | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the two consecutive numbers be $x$ and $(x+1)$.According to the problem,the difference between their squares is $35$.So,$(x+1)^{2} - x^{2} = 3

Vedclass · Accepted Answer

$17, 18$

Vedclass · Answer

(C) Let the two consecutive numbers be $x$ and $(x+1)$.According to the problem,the difference between their squares is $35$.So,$(x+1)^{2} - x^{2} = 35$.Expanding the square: $(x^{2} + 2x + 1) - x^{2} = 35$.Simplifying the equation: $2x + 1 = 35$.Subtracting $1$ from both sides: $2x = 34$.Dividing by $2$: $x = 17$.Therefore,the two consecutive numbers are $17$ and $17+1 = 18$.

The difference between the squares of two consecutive numbers is $35.$ The numbers are

Similar Questions

$A$ number when divided by the sum of $555$ and $445$ gives two times their difference as quotient and $30$ as the remainder. The number is

$(\sqrt[3]{8000} + \sqrt[3]{0.027} - \sqrt[3]{0.216})$ is equal to:

$42 \%$ of a number is $357$. What is $63 \%$ of that number?

On dividing a number by $56$,we get $29$ as remainder. On dividing the same number by $8$,what will be the remainder?

If $m$ and $n$ are positive integers and $(m-n)$ is an even number,then $(m^{2}-n^{2})$ will be always divisible by

Vedclass Test Series

Exam Paper Generator

Online Exam Module