(B) The displacement of the particle is given by $s = 6t^2 - t^3$.Velocity $v$ is the rate of change of displacement with respect to time,given by $v

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The displacement of the particle is given by $s = 6t^2 - t^3$.Velocity $v$ is the rate of change of displacement with respect to time,given by $v = \frac{ds}{dt}$.$v = \frac{d}{dt}(6t^2 - t^3) = 12t - 3t^2$.To find the time when the velocity is zero,we set $v = 0$:$12t - 3t^2 = 0$.$3t(4 - t) = 0$.This gives $t = 0 \ s$ and $t = 4 \ s$.The particle starts from rest at $t = 0 \ s$,so it will attain zero velocity again at $t = 4 \ s$.

Class 11 Physics Motion in a Straight Line Instantaneous Velocity and Speed and Velocity-time Graph

Easy

The displacement of a particle starting from rest (at $t = 0$) is given by $s = 6t^2 - t^3$. The time in seconds at which the particle will attain zero velocity again,is ..... $s$.

A
$2$
B
$4$
C
$6$
D
$8$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Motion in a Straight Line

Subtopic

Instantaneous Velocity and Speed and Velocity-time Graph

For the displacement-time graph shown in the figure,the ratio of the magnitudes of the (constant) speeds during the first two seconds and the next four seconds is

Medium

View Solution

Velocity of a particle moving along a straight line is given by $v = t^2 - 3t - 4 \, (m/s)$. Find the velocity at the instant when no net force is applicable on the particle.......$m/s$ (in $.25$)

Medium

View Solution

The acceleration of a moving body can be found from

EasyMHT CET 2024

View Solution

The positions of two cars $A$ and $B$ are given by $X_A = at + bt^2$ and $X_B = ft - t^2$. At what time will both cars have the same velocity?

Difficult

View Solution

During which time interval is the particle described by these position graphs at rest?

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The displacement of a particle starting from rest (at $t = 0$) is given by $s = 6t^2 - t^3$. The time in seconds at which the particle will attain zero velocity again,is ..... $s$.

Similar Questions

For the displacement-time graph shown in the figure,the ratio of the magnitudes of the (constant) speeds during the first two seconds and the next four seconds is

Velocity of a particle moving along a straight line is given by $v = t^2 - 3t - 4 \, (m/s)$. Find the velocity at the instant when no net force is applicable on the particle.......$m/s$ (in $.25$)

The acceleration of a moving body can be found from

The positions of two cars $A$ and $B$ are given by $X_A = at + bt^2$ and $X_B = ft - t^2$. At what time will both cars have the same velocity?

During which time interval is the particle described by these position graphs at rest?

Vedclass Test Series

Exam Paper Generator

Online Exam Module