The distance between the points (6, 8) and (3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the distance between two points $(x_1, y_1)$ and $(x_2, y_2)$,we use the distance formula:$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$Given

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(D) To find the distance between two points $(x_1, y_1)$ and $(x_2, y_2)$,we use the distance formula:$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$Given points are $(6, 8)$ and $(3, 4)$.Here,$x_1 = 6, y_1 = 8$ and $x_2 = 3, y_2 = 4$.Substituting these values into the formula:$d = \sqrt{(3 - 6)^2 + (4 - 8)^2}$$d = \sqrt{(-3)^2 + (-4)^2}$$d = \sqrt{9 + 16}$$d = \sqrt{25}$$d = 5$Therefore,the distance between the points is $5$.

The distance between the points $(6, 8)$ and $(3, 4)$ is .........

Similar Questions

If the distance between $A(1, 3)$ and $B(a, 0)$ is $3$ units,then $a = \ldots$

The distance of the point $P(2, 3)$ from the $x$-axis is

Using the distance formula,show that the points $A(-1, 4)$,$B(2, 3)$,and $C(5, 2)$ are collinear.

Find the value of $a$,if the distance between the points $A(-3, -14)$ and $B(a, -5)$ is $9$ units.

The distance of the point $P(-6, 8)$ from the origin is

Vedclass Test Series

Exam Paper Generator

Online Exam Module