The distance of point A(a cos theta, a sin th | vedclass

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(C) The coordinates of point $A$ are $(a \cos 	heta, a \sin 	heta)$ and the origin $O$ is $(0, 0)$.Using the distance formula,the distance $d$ betwe

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$a$

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(C) The coordinates of point $A$ are $(a \cos 	heta, a \sin 	heta)$ and the origin $O$ is $(0, 0)$.Using the distance formula,the distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Substituting the values,we get $d = \sqrt{(a \cos 	heta - 0)^2 + (a \sin 	heta - 0)^2}$.$d = \sqrt{a^2 \cos^2 	heta + a^2 \sin^2 	heta}$.$d = \sqrt{a^2(\cos^2 	heta + \sin^2 	heta)}$.Since $\cos^2 	heta + \sin^2 	heta = 1$,we have $d = \sqrt{a^2(1)} = \sqrt{a^2}$.Since $a \in R^{+}$,the distance is $a$.

The distance of point $A(a \cos \theta, a \sin \theta)$ from the origin is $\ldots \ldots \ldots \ldots$ $(a \in R^{+})$

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