The domain of the function $f(x) = \sqrt{\cos x}$ is
- A$[0, \frac{\pi}{2}]$
- B$[0, \frac{\pi}{2}] \cup [\frac{3\pi}{2}, 2\pi]$
- C$[\frac{3\pi}{2}, 2\pi]$
- D$[-\frac{\pi}{2}, \frac{\pi}{2}]$
Explore More
Similar Questions
The least value of $2^{(x^2 - 3)^3+27}$ is-
Difficult
View SolutionIf the range of the function $f(x) = \frac{5-x}{x^2-3x+2}$,$x \neq 1, 2$,is $(-\infty, \alpha] \cup [\beta, \infty)$,then $\alpha^2 + \beta^2$ is equal to :
DifficultJEE MAIN 2025
View SolutionThe domain of the function given by $2^x+2^y=2$ is
The range of $f(x)=\sqrt{\frac{a-|x|}{(a+1)-|x|}}, (a>0)$ is
If $R$ is the set of all real numbers and $f: R-\{2\} \rightarrow R$ is defined by $f(x)=\frac{2+x}{2-x}$ for $x \in R-\{2\}$, find the range of $f(x)$.
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo