The Earth is assumed to be a charged conducting sphere having volume $V$ and surface area $A$. The capacitance of the Earth in free space is

  • A
    $\frac{2 \pi \epsilon_0 V}{A}$
  • B
    $\frac{12 \pi \epsilon_0 V}{A}$
  • C
    $\frac{8 \pi \epsilon_0 V}{A}$
  • D
    $\frac{4 \pi \epsilon_0 V}{A}$

Explore More

Similar Questions

If the circumference of a sphere is $2 \ m$,find the capacitance of the sphere in water in $pF$. (Take dielectric constant of water $K = 80$)

Two spherical conductors $A$ and $B$ of radii $a$ and $b$ $(b > a)$ are placed in air concentrically. $B$ is given a charge $+Q$ and $A$ is grounded. The equivalent capacitance of this system is:

Match the following types of capacitors with their respective capacitance formulas:
Capacitor Type Capacitance Formula
$A$. Cylindrical capacitor $i$. $4\pi \epsilon_0 R$
$B$. Spherical capacitor $ii$. $\frac{K A \epsilon_0}{d}$
$C$. Parallel plate capacitor with dielectric $iii$. $\frac{2\pi \epsilon_0 \ell}{\ln(r_2/r_1)}$
$D$. Isolated spherical conductor $iv$. $\frac{4\pi \epsilon_0 r_1 r_2}{r_2 - r_1}$

$A$ spherical capacitor consists of two concentric spherical conductors,held in position by suitable insulating supports. Show that the capacitance of a spherical capacitor is given by $C = \frac{4 \pi \varepsilon_{0} r_{1} r_{2}}{r_{1} - r_{2}}$,where $r_{1}$ and $r_{2}$ are the radii of outer and inner spheres,respectively.

The electric field between the two spheres of a charged spherical capacitor:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo